8[c-9]=6[2c-12]-4c

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Solution for 8[c-9]=6[2c-12]-4c equation:


Simplifying
8[c + -9] = 6[2c + -12] + -4c

Reorder the terms:
8[-9 + c] = 6[2c + -12] + -4c
[-9 * 8 + c * 8] = 6[2c + -12] + -4c
[-72 + 8c] = 6[2c + -12] + -4c

Reorder the terms:
-72 + 8c = 6[-12 + 2c] + -4c
-72 + 8c = [-12 * 6 + 2c * 6] + -4c
-72 + 8c = [-72 + 12c] + -4c

Combine like terms: 12c + -4c = 8c
-72 + 8c = -72 + 8c

Add '72' to each side of the equation.
-72 + 72 + 8c = -72 + 72 + 8c

Combine like terms: -72 + 72 = 0
0 + 8c = -72 + 72 + 8c
8c = -72 + 72 + 8c

Combine like terms: -72 + 72 = 0
8c = 0 + 8c
8c = 8c

Add '-8c' to each side of the equation.
8c + -8c = 8c + -8c

Combine like terms: 8c + -8c = 0
0 = 8c + -8c

Combine like terms: 8c + -8c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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